Posted by **Kevin** on Monday, June 19, 2006 at 3:24am.

Can somebody solve this logarithm problem step by step for me please:

2(lnx)² + lnx-1 = 0

First let y = ln x be a new variable, , and solve the polynomial

2 y^2 + y - 1 = 0

2(y +1)(y - 1/2) = 0

Solutions are

y = -1 or +1/2

Thus x = e^y

and x= 1/e = 0.3679.. OR

e^0.5 = 1.6487..

- Math (Calculus) -
**Anonymous**, Friday, November 1, 2013 at 11:01pm
tg(x)sec^6(x)dx

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