Saturday

January 31, 2015

January 31, 2015

Posted by **Kevin** on Monday, June 19, 2006 at 3:24am.

2(lnx)² + lnx-1 = 0

First let y = ln x be a new variable, , and solve the polynomial

2 y^2 + y - 1 = 0

2(y +1)(y - 1/2) = 0

Solutions are

y = -1 or +1/2

Thus x = e^y

and x= 1/e = 0.3679.. OR

e^0.5 = 1.6487..

- Math (Calculus) -
**Anonymous**, Friday, November 1, 2013 at 11:01pmtg(x)sec^6(x)dx

**Answer this Question**

**Related Questions**

math - how would you solve for y in this problem: ln(y-1)-ln2 = x +lnx ln(y-1)-...

Calculus 1 - Find the derivative of y with respect to x. y=(x^6/6)(lnx)-(x^6/36...

calculus - sorry to ask a second question so soon, but i'm just not getting this...

math - I am suppose to simplify the following problems: sqrt(x)/x (isn't that ...

L'Hopital's rule - Find lim x->1+ of [(1/(x-1))-(1/lnx)]. Here is my work...

Calculus - Find the derivatives, dy/dx for the following functions. a. x^2y^4 = ...

calculus - (a) find the intervals on which f is incrs or decrs. (b) find the ...

Calculus - Find the limit as x approaches infinity of (lnx)^(1/x). This unit is ...

calc - integral of 1 to e^4 dx/x(1+lnx) 1+lnx = a => dx/x = da dx/ x(1+lnx...

College Calc - Problem: y=sqrtx ^1/x. Find DY/DX. ln(f(x))=lnx^1/2x or lnx to ...