Posted by **Chris** on Friday, September 2, 2005 at 10:08pm.

electrons are accelerated from rest over a distance of 800m to a velocity of 3x10 7 m/s. what is the acceleration of the electrons and what formula did you use to find the acceleration.

(1/2)[V(final)^2 - V(initial)^2] = a X

V(final) = sqrt (2 a X)

a = [V(final)^2/(2 X)]

=5.63*10^11 m/s^2

thank you, I was trying to start with finding the time first and couldn't figure it out. I tried changing the average velocity formula to come up with t. t=change in displacement / velocity, but wasn't sure if that was a proper way to change the formula, definitely didn't come up with the same answer. thanks.

Your method should have also worked. The distance covered is Vaverage = Vfinal/2 = a T/2.

Vaverage* T = X

Now eliminate T

Vaverage = (a/2)*(X/Vaverage)

Vaverage^2 = (a/2) X

Vfinal^2 = 2 a X

## Answer This Question

## Related Questions

- Physics - Electrons are accelerated to reach a kinetic energy of 250 eV (= 4.0 x...
- Physics - A motorcycle with a mass of 350 kg is accelerated from rest to a ...
- Physics - In a television tube, electrons initially at rest are accelerated by a...
- physics - The electrons in a TV tube are accelerated from rest through a ...
- Acceleration physics - 1. A sprinter finishes the race with a velocity of 8.9 m/...
- Physics - Starting from rest, Mr.M's bus achieves a velocity of 25 m/s in a ...
- physics - In a synchrotron, electrons are accelerated to speeds close to the ...
- science - An electron had a constant acceleration of +3.2m/s^2. At a certain ...
- Physics - In a cathode ray tube, electrons initially at rest are accelerated by ...
- Physics - In a cathode ray tube, electrons initially at rest are accelerated by ...

More Related Questions