Physics
posted by Nisar on .
I have a hard time solving this problem.
The weight of an object at the surface of a planet is proportional to the planet's mass and inversely proportional to the square of the radius of the planet. Jupiter's radius is 11 times Earth's and its mass is 320 times Earth's. An apple weighs 1.0 N on Earth. How much would it weigh on Jupiter?
wouldn't one multiply by 320(proportional to mass) and divide by 11 squared (inversely proportional to the square of distance)?
2.6N

Yes I just had a problem like this too. You would multiply by 320 and divide by 11 squared. 2.6 N would be correct for 2 signifigant digits.

The weight of an object at the surface of a planet is proportional to the planet's mass and inversely proportional to the square of the radius of the planet. Jupiter's radius is 11 times Earth's and its mass is 320 times Earth's. An apple weighs 1.0 N on Earth. How much would it weigh on Jupiter?

In cleaning out the artery of a patient, a doctor increases the radius of the opening by a factor of two. By what factor does the crosssectional area of the artery change?

The average speed of a nitrogen molecule in air is proportional to the square root of the temperature in kelvins. If the average speed is 475 m/s on a warm summer day (temperature = 300.0 kelvins), what is the average speed on a cold winter day (250.0 kelvins)?

gfd

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