If someone made a five digit number with 0,3,5,8,and 9. The number is bigger than 39 and smaller than 53 The thousandth digit is 3 times the tenth digit. What is the number?

Bigger than 39 and less than 53 means

50.

Now the decimal. The thousdnad digit is 9, tens 3. Check that.

You finish.

To find the number that fits the given criteria, we can follow these steps:

1. Determine the possible range of the number: The given conditions state that the number is bigger than 39 and smaller than 53. Based on this, we can conclude that the number falls between 40 and 52 (including both ends).

2. The thousands digit is 3 times the tens digit: Since we have determined the number falls between 40 and 52, we can represent the number as "3X5_", where "X" represents the tens digit, and "_" represents the unit digit.

3. The given digits are 0, 3, 5, 8, and 9: From the given digits, we need to select the appropriate digits for the tens and unit places.

The tens digit can only be 0 or 5 since those are the available digits. The units digit can only be 8 or 9.

Let's try both possible combinations:

- If the tens digit is 0 and the units digit is 8, the number becomes "3058".
- If the tens digit is 5 and the units digit is 9, the number becomes "3599".

4. Verify if the numbers obtained in the previous step meet the given criteria: Checking the two numbers obtained, we can see that both of them fall within the given range (40 to 52).

5. Final answer: Based on the above steps, there are two possible numbers: 3058 and 3599.