Posted by
**GetYourLeash** on
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The stopping distance of a car traveling 25mph is 61.7 feet, and for a car traveling 35 mph it is 106 feet. The stopping distance in feet can be described by the equation y = ax² +bx, where x is the speed in mph.

(a) Find the values of a and b.

(b)Use your answers from part (a) to find the stopping distance for a car traveling 55 mph.

y=ax^2+b

61.7=a*25^2 +b and

106=a*35^2 +b

subtracting the first from the second equation.

106-61.7=a(35^2-25^2) solve for a, then put that a into either equation to solve for b.

What are the features of a matrix?

What are the features of a matrix?

how do you solve this you have club a and b added together they equal 121 well if club a was increased by 4 times and club b was decresed by half what is a and b equal present

how do you solve this you have club a and b added together they equal 121 well if club a was increased by 4 times and club b was decresed by half what is a and b equal present