Posted by **Dan** on Sunday, July 17, 2005 at 7:20pm.

A person invests $7,500 part at 5% and the remainder at 4% simple interest. If the total interest at the end of the first year was $346.50, find the amount invested at 4%.

total interest=346.5=7500*.05 + x*.04

solve for x.

ooopsss, I misread the problem. The total amount invested was 7500..

total interest=346.5=(7500-x)*.05 + x*.04

solve for x.

## Answer This Question

## Related Questions

- word problem - A person invests $7,500 part at 5% and the remainder at 4% simple...
- algebra - Dilbert invests a total of $14,000 in two accounts paying 9% and 15% ...
- Algebra 2 & trig - joanna invested $7500, part at a 5.5% and the remainder at a ...
- math - Katie invested a total of ?$6000 ?, part at 3 ?% simple interest and part...
- Algebra - Maybe that was to confusing...we have a data sheet to fill out - 2 ...
- Math - Two investments are made totaling $4800. In the first year they yield a ...
- algebra - Larry Mitchel invested part of his $32,000 advance at 7% annual simple...
- simple interest - What is the amount after 1 year on $315 invested at 7%, if ...
- math - A student invests two sums of money at 3% and 4% interest, receiving a ...
- Algebra - The Smiths invested $14,000, part at 3% simple interest and the rest ...

More Related Questions