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September 2, 2014

September 2, 2014

Posted by **Jarrad Michael** on Monday, June 27, 2005 at 11:32pm.

How does your answer compare with the time it takes for the sun to disappear once its lower edge meets the horizon at sunset?

Does defreaction affect the answer?

.53/360 = x/1440

x=2.12

The sun's angular speedin the sky is 360 degrees/1440 min = 0.250 degrees/min

The time to move one solar diameter is

T = (0.53 deg)/(0.25 deg/min) = 2.1 min

Make your own observation of the actual sunset time. Refraction is one reason for a discrepancy. So is the angle that the sun's path makes with the horizon. It sets obliquely, not perpendicular to the horizon at temperate and polar latitudes.

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