Ok. so i'm supposed to find the coordinates of a line using the slope intercept method but i don't understand it!!! can some one PLEEAASE help me? also i'm supposed to graph a line using the same method and they give me the coordinates oly its in an equation form that i need to solve only i don't know how. heres the coordinates. please help me unscramble it all!
y= 3/2*(x) + 3
2y= -(x) + 2
oh, um, whoops, i kinda forgot one of the problems. its the one where i'm supposed to find the coordinates of a line. i know the coordinates, but i don't know how to how to get them. here they are.
y= -(x) + 2
PLEASE HURRY!!!! thanx. :-)
Sure, I can help you with both problems. Let's start with finding the coordinates of a line using the slope-intercept method for the equation y = mx + b.
For the first equation y = (3/2)x + 3, we can identify the slope (m) and the y-intercept (b). The coefficient of x, which is 3/2, represents the slope, and the constant term 3 represents the y-intercept.
Now, to find the coordinates, we usually need two points on the line. One way to do this is to set x=0 and solve for y, and vice versa. Let's find two points on the line using this method:
1. When x = 0:
Substitute x = 0 into the equation:
y = (3/2)(0) + 3
y = 0 + 3
y = 3
Therefore, one point is (0,3).
2. When y = 0:
Substitute y = 0 into the equation:
0 = (3/2)x + 3
(3/2)x = -3
Multiply both sides by 2/3 to isolate x:
x = -3 * 2/3 = -2
Therefore, another point is (-2,0).
Hence, the coordinates of the line y = (3/2)x + 3 are (0,3) and (-2,0).
Now, let's move on to graphing a line using the slope-intercept method.
For the equation 2y = -x + 2, we need to rewrite it in the y = mx + b form.
To do this, divide both sides of the equation by 2 to isolate y:
(2y)/2 = (-x + 2)/2
y = (-1/2)x + 1
Now, let's find two points on this line:
1. When x = 0:
Substitute x = 0 into the equation:
y = (-1/2)(0) + 1
y = 0 + 1
y = 1
Therefore, one point is (0,1).
2. When y = 0:
Substitute y = 0 into the equation:
0 = (-1/2)x + 1
(-1/2)x = -1
Multiply both sides by -2/1 to isolate x:
x = -1 * (-2/1) = 2
Therefore, another point is (2,0).
Therefore, the coordinates of the line y = (-1/2)x + 1 are (0,1) and (2,0).
I hope this explanation helps you understand how to find the coordinates of a line using the slope-intercept method and how to graph a line. Let me know if you have any further questions!