pOH Calculation

Questions (2)

What is the pOH of a 0.032 M Ca(OH)2 (strong base) solution?i solved it by doing 14=-log (0.064) 14-1.19= 12.81 but the right
1. 3 answers
2. asked by jessie
3. 601 views
What is the pOH of 2.26 M Ba(OH)2?Ba(OH)2 ==> Ba^+2 + 2OH^- (OH)^- = 2 x 2.26 M. pOH = - log(OH^-) = ??
1. 2 answers
2. asked by an
3. 515 views