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Complex Numbers
Page 6
Questions (969)
Let z and w be complex numbers such that |z| = |w| = 1, and zw is not equal to -1. Prove that
(z + w)/(zw + 1) is a real number.
2 answers
asked by
Katie
577 views
I want to solve z^5=-1
But all the examples I've seen use positive numbers. The -1 is throwing me off somewhat. Most of the
3 answers
asked by
Mrbob
537 views
Hello everyone,
Need a bit of help. (-2-2i)^5 I want to turn this into Cartesian form using the modulus. Into the form
4 answers
asked by
mrbob
420 views
Write (21 − 4i) − (16 + 7i) + 28i as a complex number in standard form.
2 answers
asked by
david
607 views
What is the polar form of (-2-2i)?
1 answer
asked by
Desperate Student
423 views
Write each expression in the standard form for a complex number, a + bi.
A. [3(cos(27°)) + isin(27°)]^5 B. [2(cos(40°)) +
3 answers
asked by
Kyle
1,819 views
Which of the following shows an expression equivalent to the product of two complex numbers, 5i • 4i?
41 - 51 9i 20 20i
3 answers
asked by
Sub-Zero
69 views
1. What is the sum of the complex numbers: (−9−i)+(−5−i)?
A. −14−2i B. −14+2i C. 14−2i D. 14+2i 2. What is the
3 answers
asked by
KiriBakuTodoDeku
47 views
What is the value of (5 + 3i) + ( 2 - 8i)?
A. 2i B. 18i c. 7 - 5i D. 7 + 11i
3 answers
asked anonymously
33 views
I may be missing something obvious here, but why is an expression such as sqrt-4 always simplified as 2i and not -2i?
1 answer
asked by
Anonymous
287 views
Do the operation and write in the form a + bi.
1/(7 + i) Is this 7/50 - (1/50)i?
1 answer
asked by
Anonymous
345 views
Perform the operation and put in standard form.
(8+square root of-12)-(4+2square root of 3i)
1 answer
asked by
Kadyn
407 views
Express square root of(1-i/1+i) in form of a+bit where a and b are real numbers
1 answer
asked by
henro
346 views
Why the polar form(2.83,45) is written a rectangular complex number like this:
2.83*cos45 + j*(2.83*sin45) I would like some
3 answers
asked by
Andrei
407 views
What is the value of iota to the power iota i.e.i^i
3 answers
asked by
Adarsh
338 views
write in standard form a+bi: (2+3i)^3
1 answer
asked by
Tim
299 views
What is the conjugate of i+3?
1 answer
asked by
Aziz
355 views
write the complex number -5 in polar form.
I don't get how to do this because arctan of b/a would be 5/0 which is a fraction with
2 answers
asked by
Ellie
500 views
#1.) Write (1-i)^10 in a+bi form.
#2.) Write (1+i)^20 in a+bi form. How do I do these? Thanks!
3 answers
asked by
Ellie
496 views
Solve (-2+i) / (3-2i) and my answer is (-8-i) / 13.
Correct?
3 answers
asked by
luis
429 views
the imaginary i or j which is equivalent to square root of -1 has a phase difference of ____ with real number 1. what's the
2 answers
asked by
reece
493 views
(6- 1/2 I)-(3+ 9/2 I)
1 answer
asked by
jay
250 views
Let z1=2(cos 2pi/3+isin 2pi/3)
what are z1^(1/3)? do not even know how to apply demoivre theorem?
1 answer
asked by
jk
472 views
Let z1=2(cos 2pi/3+isin 2pi/3)
what are z1^(1/3)?
1 answer
asked by
jk
498 views
Let z1=2(cos 2pi/3+isin 2pi/3)
what are z1^(1/3)?
5 answers
asked by
jk
531 views
Prove that if w,z are complex numbers such that |w|=|z|=1 and wz\=-1, then w+z/1+wz is a real number
I so far i have determined
2 answers
asked by
Gem
861 views
Let z1= 3-3sqrt 3i and z2= -11+i. write all answers in polar form with 0< theta< 2pi
A. what is z1 in polar form? B. what is z2
1 answer
asked by
JGF
496 views
Let z1= 3-3sqrt 3i and z2= -11+i. write all answers in polar form with 0< theta< 2pi
A. what is z1 in polar form? B. what is z2
1 answer
asked by
JGF
522 views
how do you use demoivre theorem for (-1+i)^7
1 answer
asked by
LK
431 views
demoivre theorem
(2-2i)^8
3 answers
asked by
LK
436 views
Let z and w be complex numbers such that
|2z-2|=25, |z+2w|=5, and |z+w|=2. Find |z|. I first squared both equations and expressed
1 answer
asked by
majorbill
512 views
if w is one of the complex cube roots of unity, show that 1+w equals 1. w is raised to power 2
1 answer
asked by
Shanu
462 views
How do I find complex zeros in a an equation
if the equation doesn't have the + or - value at the end can th ecomplex zero(s) be
3 answers
asked by
Please :)
468 views
1.) Write the complex number in trigonometric form r(cos theta + i sin theta) with theta in the interval [0°, 360°).
9 sqrt 3 +
2 answers
asked by
Anonymous
1,089 views
More About Complex Numbers
squ. root 5+i/squ. root 5-i I don't know if you understand this equation, but could you help me.
1 answer
asked by
Ariana
325 views
More About Complex Numbers
Multiply (4+3i)(1-i) Please show work i need help
1 answer
asked by
Alicia
339 views
More About Complex Numbers
Find the reciprocal. -1-i 2i
1 answer
asked by
Alicia
428 views
More About Complex Numbers
Find the conjugate of each number. 1.)squ root of 3-7/8i 2.) 2-mi 3.) 6 Please show work I need help
1 answer
asked by
Alicia
425 views
More About Complex Numbers
Multiply (4+3i)(1-i) Please show work i need help
1 answer
asked by
Alicia
337 views
More About Complex Numbers:
Solve x and y 4x+5y+13i=7+(6x+5y)i Please show work because I had a hard time finding the answer
1 answer
asked by
Alicia
497 views
-10-6i / -9+9i
1 answer
asked by
Monique
270 views
Sorry the first post formatted weirdly.
1. 3i - 10 --------- 8i - 5 Answer 74 65i ---- + ----- 89 89 2. 11i^2 + 1 ------------
3 answers
asked by
John
505 views
Which answer could be the result of two complex conjugates being multiplied together? (1 point)
16 9 - 9i 25 + 41i 20
3 answers
asked by
Sub-Zero
65 views
(2 - 7i) - (5 - 3i)
= -3 - 4i (1 + 2i) + (3 + 4i) = 4 + 6i
1 answer
asked by
Anonymous
321 views
1. (4i) + (2 + 8i)
= 2 + 12i 2. 6i + 4i = 10i
1 answer
asked by
Anonymous
416 views
so on 2^7i list i as -1 seven times equals out -1 or -i then what
i still cant solve i^100
1 answer
asked by
jj
296 views
2i^7
i^42 i^100
4 answers
asked by
JJ
284 views
1) 4b-5t(-a-3)i=7-8i
2) (7+4i) - (l+2i) 3) (3+2i) (-2+4i)
9 answers
asked by
anonymous
388 views
What can you multiply this expression by to get rid of the imaginary part of the denominator?
(1-2i)/2i
1 answer
asked by
Stephanie
367 views
Did I do #2 right?
2.) (1-2i)/2i (1-2i)/2i = (1-2)/i x i/i = (1i-2i)/i^2 = (1i+2) =2+1i
1 answer
asked by
Ben
256 views
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